$\frac{6}{5}m^2\cdot\frac{6}{4}n$
$\:\left(3x-2\right)\left(x^2+3x-2\right)$
$3a-3b+4c=-1$
$\left(6a-3b\right)x$
$10^3\cdot10d^{15}$
$2x^2+5x<x^2+2$
$\int x^3\cdot\cos\left(\frac{1}{2}x\right)dx$
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