$\left(1-\beta^2\right)^{-\frac{1}{2}}$

$\lim_{x\to4}\left(\frac{2x^{\frac{3}{2}}-x^2+4}{x}\right)$

$sin3xcos2x-\frac{3}{2}cos2x+8sin3x=12$

$-3\:-\:\left\{-7+2+\left[-12+\left(-8\right)\right]\right\}$

$-10d-9d^2+5d^3-10d-9d^3+5d^2-10d$

$8-12d^2-6d^4-d^5$

$\left(x-4g\right)^2$