$4k^2+64k=-180$
$\frac{dy}{dx}=16x\cdot y^3$
$2x+y;\:x=7;\:y=6$
$\left(2x\cdot3\right)^3$
$6\left(x-1\right)$
$\frac{\left(\cos\:\left(-x\right).\cos\:\left(x\right)-\sin\:\left(-x\right).\sin\:\left(x\right)\right)}{\sec\left(x\right)}$
$\int\log y^3dy$
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