$\lim_{x\to0}\left(\frac{cos\left(8x\right)-cos\left(6x\right)}{x^2}\right)$

$16x^2-\frac{1}{9}y^2$

$\left(x-1\right)\left(x+1\right)>\left(x-3\right)\left(x+4\right)$

$\left(y-d\right)^2$

$\left(s+1\right)^3$

$\cot^2\left(a\right)=\cos^2\left(a\right)+\cot^2\left(a\right)$

$9y^3-8y^2\:+3y-1;\:y=-2$