$16^{\log\left(4x\right)}$
$\left(2x-y\right)\left(-x\right)$
$\left(5a^3-3\right)\left(5a^2-20\right)$
$x-7<-9x+13$
$\log\left(x-6\right)-\log\left(3x+8\right)=\log\left(16\right)$
$\left(\frac{1}{3}+xy\right)\left(-\frac{1}{2}+xy\right)$
$1x^2-16$
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