$\:2x\:-\:4\:=\:2\:$
$-\frac{3x^4y^5}{12x^2y}$
$\int x^2\cdot\sqrt{2x-3}dx$
$\left(x-6\right)\left(3x-1\right)$
$2b+3c+4b-\left(-1\right)$
$\int_1^e\left(e^3ln\left(x\right)\right)dx$
$\arccos x=2\:arccos\left(\frac{3}{4}\right)$
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