$2x+4\cdot5x+6$
$\frac{dx}{dw}=\left(x-1\right)^2$
$\int\frac{\left(8x-2\right)}{\left(4x^2-2x+3\right)}dx$
$\lim_{x\to\infty}\left(37xe^{-x}\right)$
$\left(y^7z^5\right)^{-9}$
$m^2-64$
$2x-9\le x+4$
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