∫(2x2−9x−9)(x3−9x)dx\int\frac{\left(2x^2-9x-9\right)}{\left(x^3-9x\right)}dx∫(x3−9x)(2x2−9x−9)dx
−x2+6x−9>0-x^2+6x-9>0−x2+6x−9>0
x2+30x+xx^2+30x+xx2+30x+x
sin22.5∘cos22.5∘\sin22.5^{\circ}\cos22.5^{\circ}sin22.5∘cos22.5∘
4x−5(x3−x2−5x−3)\frac{4x-5}{\left(x^3-x^2-5x-3\right)}(x3−x2−5x−3)4x−5
c3−a3c^3-a^3c3−a3
limx→2(4x−5)\lim_{x\to2}\left(4x-5\right)x→2lim(4x−5)
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