$10q-11-12q-7$
$6x^2-24x+24$
$4x^2-16x-9$
$-7-\frac{5}{6}x=18$
$8-2u-u^2$
$6^3\:x\:\:6^4$
$\left(\frac{1}{2}x^3+1\right)\left(2x^3+x-4\right)+\left(x^2-x+8\right)$
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