$3n-6m^2+2n$
$\pi-\frac{1}{4}$
$9\cdot22$
$\left(8-y^3\right)^2$
$\left(y^3-5\right)\cdot\left(y^3+5\right)$
$\cos\left(x-\frac{\pi}{8}\right)=\frac{1}{\sqrt{2}}$
$2y^2\:+\:2y^2$
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