$\frac{18x^3+24x^2+20x+11}{6x+4}$

$y=\frac{\sin x\cos^{2}x\tan^{5}x}{\sqrt[3]{x}}$

$\cos\left(b\right)^2$

$\left(-3\right)\cdot\left(-5\right)\cdot10$

$\lim_{x\to0}\left(\frac{cos3x-1}{6x^2-sin3x}\right)$

$\left(7a+3b\right)^2\left(a-2b\right)^2$

$\lim_{x\to0}\left(\frac{x+\sqrt{d+x}-\sqrt{d}}{x}\right)$