$\lim_{x\to0}\left(\frac{x\cdot8^x}{8^x-1}\right)$

$\int\left(18x^2\left(3x^3+3\right)^2\right)dx$

$\ln\left(x+7\right)\ln\left(x+7\right)$

$\int8x\cdot\log\left(x\right)dx$

$\int\:\frac{1}{\left(x-6\right)^2\left(x-3\right)}dx$

$\lim_{x\to8}\frac{x^2-9x+8}{x-8}$

$16p^2-40pq+25q^2$