$\:f\left(x\right)\:=\:2\:x\:2+1\:\:\:\left[2,12\right]$
$\frac{15a^7}{\left(3a^2\right)^2}$
$3x+1>x-15$
$y=\arctan\left(\frac{x}{7}\right)+\frac{3x-9}{7\left(x^2+2\right)}$
$\frac{4a}{b}-a^5$
$\left(2xyz\:-\:6xz^3\right)^2$
$3+26+76+40$
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