$10a^2+11a+8.3$
$64x^2y^2-9a^6$
$\int_{-\infty}^6\left(xe^{-\frac{r}{3}}\right)dx$
$\left(a^2x+by^3\right)\left(ax^2-by^3\right)$
$8b^2+7b-1$
$\lim_{x\to0}2+\frac{5}{x^2}$
$4-\left(6+3-1\right)$
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