$2x=2$
$\left(10x^{10}+5\right)^2$
$100a^2-60a^2b+ab^2$
$5+19\cdot2$
$a^2\cdot b^3\sqrt[3]{a^8\cdot b^7}\cdot ab$
$\frac{\cos\left(-a\right)}{\sec\left(-a\right)+\tan\left(-a\right)}=1+\sin\left(a\right)$
$\frac{d^2}{dx^2}\left(3\cdot\csc\left(3x\right)\cot\left(3x\right)\right)$
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