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Exercise

$\frac{3x}{2x^{2}-5}\cdot\frac{-2x+5}{6x-9x^{2}}$

Step-by-step Solution

1

Multiplying fractions $\frac{3x}{2x^2-5} \times \frac{-2x+5}{6x-9x^2}$

$\frac{3x\left(-2x+5\right)}{\left(2x^2-5\right)\left(6x-9x^2\right)}$

Final answer to the exercise

$\frac{3x\left(-2x+5\right)}{\left(2x^2-5\right)\left(6x-9x^2\right)}$

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