$\left(\left(6^2\right)^2\right)^0$
$\frac{dy}{dx}=y^2-6y-16$
$y'=1-x-y\:$
$6x\:4\:-\:30x\:3\:+\:2x\:2$
$4x^2-2x+5=0$
$-\frac{\sin\left(x^2\right)}{\cos\left(x^2\right)}$
$4x^2=21$
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