∫(x+2)⋅ln(x)dx\int\left(x+2\right)\cdot ln\left(x\right)dx∫(x+2)⋅ln(x)dx
8−(−4)2⋅3+9(−3)8-\left(-4\right)^2\cdot3+9\left(-3\right)8−(−4)2⋅3+9(−3)
dydx=1sin(5y)\frac{dy}{dx}=\frac{1}{\sin\left(5y\right)}dxdy=sin(5y)1
dydx=cos(5x)\frac{dy}{dx}=cos\left(5x\right)dxdy=cos(5x)
(x2+4y2)dydx=xy\left(x^2+4y^2\right)\frac{dy}{dx}=xy(x2+4y2)dxdy=xy
7x2−19x+107x^2-19x+107x2−19x+10
(34c+76)(34c−15a)\left(34c+76\right)\left(34c-15a\right)(34c+76)(34c−15a)
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