$-18\:+\:18\:+\:1\:+\:4\:=\:$
$\lim_{x\to2\pi}\left(\frac{x-2\pi}{\sin\left(x\right)}\right)$
$\frac{2^7}{2^4}$
$6x^2+5x-4=0$
$a^2+4a-12=0$
$x^{2\:}+6x=7$
$1\left(x\right)^2\cdot\cos\left(x\right)^2$
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