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3x+3+2x−3=12(x+3)(x−3)\frac{3}{x+3}+\frac{2}{x-3}=\frac{12}{\left(x+3\right)\left(x-3\right)}

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2x2−1x3−x\frac{2x^2-1}{x^3-x}

−20.20+180-20.20+180
3x+3 +2x−3 =12(x+3)(x−3) 
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