$12.78+4$
$a^2b\cdot\left(-b^3\right)$
$x^2+8+\left(\frac{8}{2}\right)^2$
$\left(\sqrt{x-\frac{3}{x}}\right)^{10}$
$\sqrt[3]{\frac{a^{11}}{a^2}}$
$x^3+\:x^2\:-4x\:-\:4\:$
$\frac{d}{dx}x^6+x^5$
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