$3x\ge13$
$\frac{dy}{dx}\left(6+x^4\right)=\frac{x^3}{y}$
$\left(\frac{2}{5}x-2\right)^2$
$\sqrt[3]{2.4142}\sqrt[3]{\sqrt{2}-1}$
$3\left(-2\right)+3\left(4\right)$
$\left(7x\right)+\left(5yz\right)^2$
$\left(t\:-\:1\right)\left(t\:+\:1\right)\left(t^2\:+\:1\right)$
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