$\frac{1+\sec\left(x\right)}{\csc\left(x\right)+\cot\left(x\right)}=\tan\left(x\right)$
$2\left(x+7\right)=10$
$x^3y'+y=0$
$y'\:=6$
$\int\tan^2\:2x\:sec^2\:2x\:dx$
$\frac{dy}{dx}\left(x^2cos^2\left(y\right)=2x^4\right)$
$\frac{cosb}{cotb}\cdot\frac{cot^2b}{cos^2b}$
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