$\left(2x+6\right)\cdot\left(6x^2+10x+2\right)$
$\frac{dy}{dx}=\frac{\left(x^2+2y^{2\:}\right)}{xy}$
$\left(6x^3-5y\right)^2$
$\left(4x+3y-8z\right)+\left(6y-3z\right)$
$w^2-16w+10$
$\int_{t-1}^t\left(2\right)dx$
$\frac{dy}{dx}+\frac{2y}{2x+5}=7x+3$
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