$\left(3\:-\:4x\right)^2$

$4\left(-4j\:+\:6\right)$

$\sin\left(x\right)^2-\sin\left(x\right)=5\cos\left(x\right)^2-4$

$\left(\frac{2x}{3}-\frac{3x^2}{a}\right)^2$

$\frac{dy}{dx}=\frac{1}{\left(x^2-x\right)cos^3y}$

$\frac{d}{dx}\left(x^2\:\cdot\:y^2\:=\:b\right)$

$\sqrt{\left(4a^5b^8\right)^3}$