$6x^2+60x+24=0$
$\int_{-1}^3\left(\frac{x}{2-x}\right)dx$
$\frac{dy}{dx}=\frac{2\cos\left(x\right)}{3y^2}$
$sin^4x-\frac{1}{2}sin^2x+\frac{1}{16}$
$\int\frac{2x+3}{x^2}dx$
$t^2+12+24$
$4y+3>2y+14$
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