$x^2+4x=13$
$10,2+6.5$
$63\left(0\right)^2$
$0,25\:x\:1,6$
$\left(x-x\right)^6$
$-7x+3\ge-18$
$\left(3a^2b^3\right)\left(4a^3b^4\right)^2$
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