Exercise
$\frac{2x^3-4x^2-5}{x^2+3}$
Step-by-step Solution
1
Divide $2x^3-4x^2-5$ by $x^2+3$
$\begin{array}{l}\phantom{\phantom{;}x^{2}+3;}{\phantom{;}2x\phantom{;}-4\phantom{;}\phantom{;}}\\\phantom{;}x^{2}+3\overline{\smash{)}\phantom{;}2x^{3}-4x^{2}\phantom{-;x^n}-5\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}+3;}\underline{-2x^{3}\phantom{-;x^n}-6x\phantom{;}\phantom{-;x^n}}\\\phantom{-2x^{3}-6x\phantom{;};}-4x^{2}-6x\phantom{;}-5\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}+3-;x^n;}\underline{\phantom{;}4x^{2}\phantom{-;x^n}+12\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}4x^{2}+12\phantom{;}\phantom{;}-;x^n;}-6x\phantom{;}+7\phantom{;}\phantom{;}\\\end{array}$
$2x-4+\frac{-6x+7}{x^2+3}$
Final answer to the exercise
$2x-4+\frac{-6x+7}{x^2+3}$