$\int\left(\frac{tan^{-1}\left(5x\right)}{x}\right)dx$

$\left(2x-b\right)^2-\left(3y+b\right)^2$

$9x^2+10=12x$

$\int_2^4\left(\frac{\left(2x^3\right)}{\sqrt{\left(x^2-4\right)}}\right)dx$

$2\frac{d^2y}{dx^2}-11\frac{dy}{dx}+12y=0$

$100-8+\left(-5\right)+1-\left(-20\right)$

$-8+4-9-7$