$-t^2+4t-3$
$3e^{2x}\cdot\:tan\left(3y\right)dx+\left(2-e^x\right)\cdot\:\:sec^2\left(3y\right)dy=0$
$y\:2\:-\:\:\:6y\:-\:72\:=\:$
$\frac{du}{dx}=\frac{u}{x}$
$\frac{dy}{dx}=\frac{-y^2}{x^2}$
$sen\:a\:\:cos\:a\:\left(tg\:a\:+\:ctg\:a\right)=1$
$\left(8a^3b^2\right)\left(5a^6b\right)$
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