$\frac{\left(2x^5+4x^2-3\right)}{\left(x^2-2\right)}$
$\frac{dy}{dx}+7y-4e^{-5x}=0\:,\:y\left(0\right)=3$
$\left(4x-7xy\right)$
$\frac{x^5-x^3+x}{x-2}$
$\left(1-\ln\left(y\right)\right)\frac{dy}{dx}+1-\ln\left(x\right)=0$
$2x^2+3xy^2+2x^3y$
$\left(x-1\right)\left(x+3\right)\left(x-4\right)\left(x-4\right)\left(x-4\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!