$\frac{x^2-4x-5}{x}$
$26m+10x+14v+z-12m+15x-20z-12x-5m-5z-11z-7x$
$\lim_{x\to\infty}\:\frac{x^3}{x+1}$
$\frac{tan\theta\:-sen\theta\:}{sen^3\theta\:}$
$-45:\:-\:7$
$\lim_{x\to2}\left(\frac{x-2}{x^2-5x+6}\right)$
$\int\frac{1}{\left(2x\right)^2}dx$
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