$\frac{20x^2+12x}{4x}$
$4+16\left(-3\right)-5$
$\frac{\left(1\right)}{x\cdot\left(\left(x^2\right)-16\right)}$
$\left(4+\left(8-\left(5-2\right)+\left(7-3\right)\right)+\left(\left(-3\right)-\left(-8\right)+13\right)\right)$
$\left(-8x-7\right)^2$
$\int\frac{x}{\left(4x+9\right)^2}dx$
$-7\left(-11-2\right)$
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