$\left(x-1\right)+\left(x+3\right)$
$\frac{d^5}{dx^5}\left(\tanh\left(x\right)\right)$
$10+2x-3x$
$y\left(y-1\right)+x=2$
$y'=-3y+6x$
$1+x\le1$
$4b^2+20bm+25m^2$
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