$y=\:\left(3x^3+2x\right)\frac{1}{2}$
$8b-8b-5b^2+-2b+-b$
$\int x^-7dx$
$x^4+16x^2+16$
$64y^2-48y+18=9$
$\left(2x+\frac{1}{2}\right)\left(2x-\frac{3}{4}\right)$
$3x-x+2>6x-5$
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