$\left(1.96\right)^2$
$1235\cdot10^3$
$x^2-x^{-2}=0$
$\left(\frac{1}{3}x^2+5y\right)^2$
$\frac{dy}{dx}=\frac{-5x}{ye^{x^2}}$
$3+5x+98-2x$
$\lim_{x\to0}\left(\frac{1-\cos6\left(x\right)}{x^2}\right)$
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