$6a^2x+4ab$
$\frac{2x+6}{2}-2x=3$
$37.3\cdot10^{-2}\cdot0.01\cdot10^2$
$3x^4y^3+6x^3y^4+18x^2y^5$
$1x^2-3x+12x-6\left(x-6x-9\right)$
$\lim_{x\to-\infty\:}\left(\frac{x^2+x}{\left(x^2+3\right)^2}\right)$
$\int\left(\frac{1}{x^2-2x+7}\right)dx$
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