$\frac{1}{x}+\frac{12}{x-3}=-4$

$\left(x+0\right)^2=36$

$7w^2+4+4w+6w^2+2+3w^2$

$m^2+5m+4$

$\frac{1+\log\theta}{\left(d+\sen\theta\right)^{2}}d\theta$

$\int\frac{x^2+1}{\left(\left(x-2\right)\left(x-3\right)\left(x-6\right)\right)}dx$

$\int_{-4}^{-2}\left(\frac{1}{x}\right)dx$