$\left(\frac{0.096}{3.4}\right)^{0.7}$
$3x^2-5x-9;\:x=2$
$\frac{d}{dx}3x-5$
$\frac{x^5+4x^2}{x+3}$
$\lim_{x\to0}\left(\frac{x^2}{\sec\left(x\right)-1}\right)$
$\:\int\left(2x+1\right)\left(x^2+x-3\right)dx$
$\frac{3}{4}\sqrt[7]{\left(4x^4-3x^3\right)^4}$
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