$\left(2\frac{1}{3}\right)^{-2}$
$4+3+5+2\:+4+4.24$
$17+28:\left(5+3-1\right)-3-7$
$\frac{\left(8ab^5\right)}{\left(2a^4b^4\right)}$
$x^2-25x+80$
$\left(-9\right)\:-\:\left(-6\right)\:$
$ab\:+\:abc\:+\:abcd\:+\:abcde\:+\:abcdef$
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