$\left(10x\:-\:9\right)\left(3x\:-\:9\right)$
$\int\left(\frac{x^2+3x}{x}\right)dx$
$\int\frac{\left(x^2\right)}{\left(\sqrt{1+x^2}\right)^5}dx$
$4x^2-8x=0\:$
$-3x^2-\:3x^2-3x^2$
$x^{2}-9=72$
$3\left(4x-2\right)$
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