$\left(-x^2+2x\right)^2-\left(-4\sqrt{x}\right)^2$
$\left(4-\left(-1\right)\right)\left(6-\left(-1\right)\right)$
$\int\frac{\frac{1}{\cos\left(lnx\right)}\cdot tan\left(lnx\right)}{x}dx$
$-3-x-2x+3x^2$
$b+3=-3$
$\int\frac{4x}{4x\left(x+4x\right)}dx$
$\int\frac{x^2+1}{x}\:dx$
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