$\frac{dy}{dx}+5=1$
$9x^2-42x\:-21$
$\left(x+3+\frac{\sqrt{160}}{4}\right)\cdot\left(x+3-\frac{\sqrt{160}}{4}\right)$
$\lim_{x\to\infty}7x+4$
$\int\frac{x-2}{x\left(x^2-4x+5\right)}dx$
$\left(x-8\right)\left(x+17\right)$
$\int\frac{8x+2}{x^2+6x-16}dx$
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