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Exercise

$\frac{121m^8-n^2}{11m^4-n}$

Step-by-step Solution

1

Aplicamos a regra: $\frac{a+b}{c+f}$$=c-f$, onde $a=121m^8$, $b=-n^2$, $c=11m^4$ e $f=\left(-n\right)$

$11m^4+n$

Final answer to the exercise

$11m^4+n$

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