3 tan x + 2 sec x3\:tan\:x\:+\:2\:sec\:x3tanx+2secx
(cos(z)−1+z22)z8\frac{\left(cos\left(z\right)-1+\frac{z^2}{2}\right)}{z^8}z8(cos(z)−1+2z2)
∫(e5x−2)2dx\int\left(e^{5x}-2\right)^2dx∫(e5x−2)2dx
3x2y2+9x2y2−18xy23x^2y^2+9x^2y^2-18xy^23x2y2+9x2y2−18xy2
2a2−2a=02a^2-2a=02a2−2a=0
ddx(10x2+4xy+3y2=0)\frac{d}{dx}\left(10x^2+4xy+3y^2=0\right)dxd(10x2+4xy+3y2=0)
(2x−5y4)4\left(2x-5y^4\right)^4(2x−5y4)4
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