$\left(3^{3n}\right)^3$
$-3x^2+8x+3$
$\left(-3\right)\left(3+5\right)-4\left(-9-5\right)$
$8 x ^ { 3 } + 6 x$
$\int\frac{3a^2+6a+2}{a^2+3a+2}dx$
$9\left(6-3x\right)$
$\frac{16x^2-8x+1}{4x-1}$
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