$\frac{dm}{dn}=m-m^2$
$2y^3+4y^2+3y\cdot2$
$6a^{x+3}+8a^{x+1}$
$\tan\left(x\right)+2\sin^2\left(x\right)$
$20\:por\:12$
$\left(2x^2\cdot x\right)^3\cdot\left(x^{-1}\cdot x^2\right)^{-2}$
$\frac{d}{dx}\sqrt{\frac{x-5}{x^8+4}}$
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