$$256a^{12}-289b^4m^{10}$$

$$\:\frac{\:\:27z^{13}\:\:\:\:y^4\:\:}{3z^7\:y^8}$$

$$\frac{dy}{dx}=\frac{3y}{2x}$$

$$\left(w+2x-3y-4z\right)^2$$

$$15+9x+x$$

$$\frac{1}{y-1}dy=\frac{e^x}{2\left(e^x+4\right)}dx$$

$$\sqrt{1-5x^2}y=x$$