Applying the trigonometric identity: $1-2\cos\left(\theta \right)^2 = -\cos\left(2\theta \right)$
Using the sine double-angle identity: $\sin\left(2\theta\right)=2\sin\left(\theta\right)\cos\left(\theta\right)$
Multiply the fraction and term in $-2\cdot \left(\frac{1}{2}\right)\sin\left(2y\right)$
Multiply $-2$ times $1$
Divide $-2$ by $2$
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