$t^{\frac{1}{3}}\left(t-4\right)$
$x+2\left(2x^3-8x^2-7x+20\right)$
$4r+9r-11r+7r$
$5x^2-45x+20=0$
$7\left(2x-3\right)-4=3x+4\left(3x-5\right)$
$-0.05+15.22$
$\lim_{x\to-\infty}\left(\frac{e^x}{1+e^x}\right)$
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